Solve any equation in the form ax² + bx + c = 0 for real or complex roots, with the discriminant and every step shown.
The discriminant (b²-4ac) is calculated first to determine the type of roots, then the quadratic formula is applied to find the exact value(s) of x.
Any equation in standard form ax² + bx + c = 0 (with a ≠ 0) can be solved using the quadratic formula, regardless of whether it factors nicely.
Example: for x²-3x-4=0 (a=1, b=-3, c=-4), the discriminant is 9+16=25, giving x = (3±5)/2, so x = 4 or x = -1.
| Discriminant | Root type |
|---|---|
| Positive | Two distinct real roots |
| Zero | One repeated real root |
| Negative | Two complex conjugate roots |
What is the quadratic formula? x = (-b ± √(b²-4ac)) ÷ 2a, used to solve any equation in the form ax² + bx + c = 0.
What is the discriminant and what does it tell you? The discriminant is b²-4ac. If it's positive, the equation has two real roots; if zero, one repeated real root; if negative, two complex roots.
What does it mean for a quadratic to have complex roots? Complex roots occur when the discriminant is negative, meaning the parabola never crosses the x-axis — the solutions involve the imaginary unit i (√-1).
Can the quadratic formula be used for any quadratic equation? Yes, as long as the equation is in standard form ax² + bx + c = 0 with a not equal to zero — the quadratic formula always works, unlike factoring, which only works cleanly for some equations.
What is an example of solving with the quadratic formula? For x²-3x-4=0 (a=1, b=-3, c=-4), the discriminant is 9+16=25, giving x = (3±5)/2, so x = 4 or x = -1.
Example 1 — Two real roots: x²-3x-4=0 → x = 4 or x = -1.
Example 2 — One repeated root: x²-4x+4=0 → discriminant = 0 → x = 2.
Example 3 — Complex roots: x²+2x+5=0 → discriminant = -16 → x = -1 ± 2i.